5t^2-7t-605=0

Solution for 5t^2-7t-605=0 equation:

5t^2-7t-605=0

a = 5; b = -7; c = -605;
Δ = b2-4ac
Δ = -72-4·5·(-605)
Δ = 12149
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-7)-\sqrt{12149}}{2*5}=\frac{7-\sqrt{12149}}{10}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-7)+\sqrt{12149}}{2*5}=\frac{7+\sqrt{12149}}{10}
$